Remove use gulp.start()

gulp.start() is never officially supported by gulp, it's better to use the functionality provided by gulp.watch(). 

See: gulpjs/gulp#755
This commit is contained in:
Bo Lu 2018-02-19 22:29:30 +11:00 committed by Shawn Erquhart
parent 72a5f0d086
commit 3668131f2e
1 changed files with 4 additions and 5 deletions

View File

@ -7,7 +7,6 @@ import postcss from "gulp-postcss";
import cssImport from "postcss-import";
import cssnext from "postcss-cssnext";
import BrowserSync from "browser-sync";
import watch from "gulp-watch";
import webpack from "webpack";
import webpackConfig from "./webpack.conf";
@ -63,10 +62,10 @@ gulp.task("server", ["hugo", "css", "js", "fonts"], () => {
baseDir: "./dist"
}
});
watch("./src/js/**/*.js", () => { gulp.start(["js"]) });
watch("./src/css/**/*.css", () => { gulp.start(["css"]) });
watch("./src/fonts/**/*", () => { gulp.start(["fonts"]) });
watch("./site/**/*", () => { gulp.start(["hugo"]) });
gulp.watch("./src/js/**/*.js", ["js"]);
gulp.watch("./src/css/**/*.css", ["css"]);
gulp.watch("./src/fonts/**/*", ["fonts"]);
gulp.watch("./site/**/*", ["hugo"]);
});
/**